擅长:python、mysql、java
<pre><code>#!/usr/bin/python
s2 = "qsrqq"
s1 = "qqtrr"
counts1=0
counts2=0
letters= set.intersection(set(s1), set(s2))
print ("letters: "+str(letters) + " intersection count: "+str(len(letters)))
for letter1 in set(s1):
print ("letter1 " + str(letter1))
counts1 += 1
for letter2 in set(s2):
print ("letter2 " + str(letter2) )
counts2 += 1
print ("counts1 " + str(counts1) + " counts2 " + str(counts2) )
counts = min(counts1, counts2)
print (counts)
</code></pre>
<p>这导致:</p>
^{pr2}$
<p>分析,2是正确答案(q和r是两者唯一的共同字母),3是任一组唯一值的较低数目。在</p>