擅长:python、mysql、java
<p>熊猫的直接解决方案是:</p>
<pre><code>df["Unique"] = df["Ligand_miss"][~df["Ligand_miss"].isin(df["Ligand_hit"])].drop_duplicates()
Ligand_hit Ligand_miss Unique
0 M00001 M00005 M00005
1 M00002 M00001 NaN
2 M00003 M00007 M00007
3 M00004 M00003 NaN
</code></pre>
<p>这将为唯一值提供索引查找。在</p>