将12小时时钟时间转换为24小时时钟时间

Question

我知道在S/O网络上有很多答案，但我在HackerRank python 3 shell中遇到了一个不寻常的错误，下面的代码在Jupyter notebook中运行良好

time1=input()
l=time1.split(':')
if 'PM' in l[2]:
    l[0]=int(l[0])+12
    l[2]=l[2].rstrip('PM')
elif 'AM' in l[2]:
    l[2]=l[2].rstrip('AM')
    if l[0]=='12':
        l[0]="0"
time2=''
for i in range(2):
    time2+=str(l[i])+':'
time2+=l[2]
print(time2)

这是challenge：

Given a time in 12-hour AM/PM format, convert it to military (24-hour) time.

Note:

• 12:00:00AM on a 12-hour clock is 00:00:00 on a 24-hour clock.
• 12:00:00PM on a 12-hour clock is 12:00:00 on a 24-hour clock.

Example

• s = '12:01:00PM'

  Return '12:01:00'.

• s = '12:01:00AM'

  Return '00:01:00'.

Function Description

Complete the timeConversion function in the editor below. It should return a new string representing the input time in 24 hour format.

timeConversion has the following parameter(s):

• string s: a time in 12 hour format

Returns

• string: the time in 12 hour format

Input Format

A single string s that represents a time in 12-hour clock format (i.e.: hh:mm:ssAM or hh:mm:ssPM).

Constraints

• All input times are valid

Sample Input 0

07:05:45PM

Sample Output 0

19:05:45

我确实试过运行同样的案例，在H/R上出现错误，但在J/p笔记本上工作正常

另外，我知道这可能是我提出的一个超级基本的问题，但请原谅，我还是个新手：）

Answer 1

似乎有两个问题：

• 当输入时间为12:00:00PM时，代码返回无效结果（24:00:00）。在这种情况下，它应该保持12个不变
• 当输入为12:00:00AM时，代码返回的小时数只有1位，而2位是必需的

因此，改变这一点：

l[0] = int(l[0]) + 12

致：

if l[0] != "12":
    l[0] = int(l[0]) + 12

改变这一点：

l[0] = "0"

致：

l[0] = "00"

有了这一点，它就会起作用。请注意，要求您编写timeConversion函数的主体，因此您的代码中不应该有硬编码的time1=

最终的代码可能是这样的：

def timeConversion(time1):
    h = time1[0:2]
    if time1[-2:] == "PM'":
        if h != "12":
            h = str(int(h) + 12)
    elif h == '12':
        h = "00"
    return h + time1[2:-2]

Answer 2

def conv24(time):
    """
    Converts 12HR clock to 24HR clock
    time should be either 
    'hh:mm:ssAM' or 'hh:mm:ssPM'
    """

    l = time.split(':')
    if 'PM' in l[2]:
        v = int(l[0])
        if v < 12 and v > 0:
            v += 12
            l[0] = str(v)
        l[2] = l[2].strip('PM')
    elif 'AM' in l[2]:
        v = int(l[0])
        if v == 12:
            l[0] = '00'
        l[2] = l[2].strip('AM')
    res = ''
    for i in l:
        res += i + ":"
    return res.rstrip(':')