<p>在您的图像中,问题似乎是白色矩形。我的方法是检查每一行,如果这一行包含许多接近白色的像素(255255),那么就把这一行变成黑色</p>
<p>这是我的密码:</p>
<pre><code>import cv2
import numpy as np
import random as rng
img=cv2.imread("/ur/image/directory/obstacle.png")
height, width, channels = img.shape
cv2.imshow('Source',img)
# Check each line and eliminate white rectangles(if line consist white pixels more than limit)
for x in range(0,height):
white_counter = 0
for y in range(0,width):
if img[x,y,0] >= 180 and img[x,y,1] >= 180 and img[x,y,2] >= 180:
white_counter = white_counter + 1
if white_counter>10:
for y in range(0,width):
img[x,y,0] = 0
img[x,y,1] = 0
img[x,y,2] = 0
cv2.imshow('Elimination White Rectangles', img)
# Find contours and draw rectangle for each
src_gray = cv2.cvtColor(img, cv2.COLOR_BGR2GRAY)
threshold = 300
canny_output = cv2.Canny(src_gray, threshold, threshold * 2)
contours, _ = cv2.findContours(canny_output, cv2.RETR_TREE, cv2.CHAIN_APPROX_SIMPLE)
contours_poly = [None]*len(contours)
boundRect = [None]*len(contours)
for i, c in enumerate(contours):
contours_poly[i] = cv2.approxPolyDP(c, 3, True)
boundRect[i] = cv2.boundingRect(contours_poly[i])
rng.seed(12345)
drawing = np.zeros((canny_output.shape[0], canny_output.shape[1], 3), dtype=np.uint8)
for i in range(len(contours)):
color = (rng.randint(0,256), rng.randint(0,256), rng.randint(0,256))
cv2.rectangle(drawing, (int(boundRect[i][0]), int(boundRect[i][1])), \
(int(boundRect[i][0]+boundRect[i][2]), int(boundRect[i][1]+boundRect[i][3])), color, 2)
cv2.imshow('Output', drawing)
cv2.waitKey(0)
cv2.destroyAllWindows()
</code></pre>
<p>消除白色矩形:</p>
<p><a href="https://i.stack.imgur.com/MiygX.png" rel="nofollow noreferrer"><img src="https://i.stack.imgur.com/MiygX.png" alt="enter image description here"/></a></p>
<p>结果:</p>
<p><a href="https://i.stack.imgur.com/Zxu3d.png" rel="nofollow noreferrer"><img src="https://i.stack.imgur.com/Zxu3d.png" alt="enter image description here"/></a></p>