我想根据odoo中另一个模型的状态更新模型中的状态
我尝试更新员工模型中的员工状态:
where work_order_state= "progress" set employee_state="unavailable"
我尝试了onchange函数,但它使用较少,尝试了update函数,但它不返回任何内容,并尝试更新/创建相同的内容 这是我在堆栈溢出中的第一个问题,任何人都可以帮助我
Python:
from typing import ByteString
from odoo import models, fields, api,exceptions, _
from odoo.exceptions import ValidationError, UserError
""" Defines manufacturing resource """
class MrpWorkcenter(models.Model):
_inherit = 'mrp.workcenter'
_description = 'Work Center'
employee_ids = fields.One2many('hr.employee', 'employee_id', string="Resource")
workcenter_id = fields.Many2one("mrp.workorder")
employee_id = fields.Many2one('hr.employee', string="Name")
resource_state = fields.Many2one('hr.employee', string="State")
class Employee(models.Model):
_inherit = "hr.employee"
_description = "Employee"
is_resource = fields.Boolean('Resource')
employee_id = fields.Many2one('mrp.workcente', string="Resource")
resource_state = fields.Selection([
('available', 'Available'),
('unavailable', 'Unavailable')],
string='State')
workcenter_ids = fields.One2many("mrp.workcenter", 'employee_id',string="Work Center")
workorder_id = fields.Many2one("mrp.workorder", string="Resource")
@api.multi
def _update_state(self, vals):
for res in self:
record_to_update= self.env['hr.employee'].search()
if record_to_update.exists():
for rtn in self:
record_to_search= self.env['mrp.workorder'].search([('state', '=','progress')])
if record_to_search.exists():
vals={
'resource_state':'unavailable'
}
record_to_update.write(vals)
return rtn
return res
class ManufacurWorkorder(models.Model):
_inherit = 'mrp.workorder'
_description = 'Work Order'
workcenter_id = fields.Many2one("mrp.workcenter")
employee_ids = fields.Many2many('hr.employee', string="Resource")
state = fields.Selection([
('pending', 'Pending'),
('ready', 'Ready'),
('progress', 'In Progress'),
('done', 'Finished'),
('cancel', 'Cancelled')], string='Status',
default='pending')
workorder_id = fields.Many2one('mrp.workorder')
XML:
<?xml version="1.0" encoding="utf-8"?>
<odoo>
<data>
<!-- Created by Mehad Mregany at 01022021 10:30 am -->
<!-- Edited by Mehad Mregany at 07022021 08:30 am -->
<!-- Manufacture Resource -->
<record id="manufacture_resource_hr_form_id" model="ir.ui.view">
<field name="name">hr.employee.form</field>
<field name="model">hr.employee</field>
<field name="inherit_id" ref="hr.view_employee_form"/>
<field name="arch" type="xml">
<field name="mobile_phone" position="replace">
<field name="is_resource"/>
</field>
<field name="work_phone" position="replace">
<field name="resource_state" attrs="{'invisible':[('is_resource', '=', False)]}"/>
</field>
<field name="coach_id" position="replace">
<field name="workcenter_ids" widget="many2many_tags"
attrs="{'invisible':[('is_resource', '=', False)]}"
options="{'no_create':True,'no_create':True }"/>
</field>
</field>
</record>
<record id="manufacture_resource_hr_tree_id" model="ir.ui.view">
<field name="name">hr.employee.tree</field>
<field name="model">hr.employee</field>
<field name="inherit_id" ref="hr.view_employee_tree"/>
<field name="arch" type="xml">
<field name="name" position="after">
<field name="is_resource"/>
</field>
<field name="work_phone" position="replace">
<field name="resource_state"/>
</field>
</field>
</record>
<record id="manufacture_resource_workorder_form_id" model="ir.ui.view">
<field name="name">mrp.workorder.form</field>
<field name="model">mrp.workorder</field>
<field name="inherit_id" ref="mrp.mrp_production_workcenter_form_view_inherit"/>
<field name="arch" type="xml">
<notebook>
<page string="Resource">
<field name="employee_ids"
domain="[('resource_state','=','available'), ('is_resource','=','True')]">
<tree string="Resource" editable="bottom">
<field string="Employee" name="name" />
</tree>
</field>
</page>
</notebook>
</field>
</record>
</data>
</odoo>
正如我从您的分布式代码中得到的,您希望在mrp.workorder中更新hr.employee-based状态中的状态 您可以更新您的代码,使其看起来像这样。首先,将您的代码移动到mrp.workorder中
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