擅长:python、mysql、java
<p>这很有效</p>
<pre><code>keywords = ["HIPAA", "ERP(2.0)"]
r = re.compile('|'.join([re.escape(w) for w in keywords]), flags=re.I)
word = r"HIPAA and ERP(2.0)"
r.findall(word)
</code></pre>
<p><strong>输出</strong></p>
<pre><code>['HIPAA', 'ERP(2.0)']
</code></pre>