擅长:python、mysql、java
<p>我相信numpy数组的维数不是1,您需要执行与数组维数相同的求和次数,才能获得单个和值</p>
<pre><code> [1,2,3]
sum gives : 6
[[1,2,3],[1,2,3]]
sum gives : [2,4,6]
doing a second sum opertion gives
: 12 (single value)
</code></pre>
<p>在打印数据之前,您可能需要再添加一个“总和(结果)”(如果图像是二维的)</p>
<p>例如:</p>
<pre><code> numpyImg2.append(img2)
diff = numpyImg1[0] - numpyImg2[0]
result = sum(abs(diff))
result = sum(result) >> Repeat
print("difference:",result)
</code></pre>