`request.json（）`throwing“响应不能解释为json”使用请求

Question

import requests
import json

def get_movies_from_tastedive(movie):
    d = {"q":movie,"type":"movie","limit":"5"}
    movies = requests.get("https://tastedive.com/api/similar",params=d)
    x = movies.json()
    print(x)

我正在运行上面的代码，试图访问TasteDive API，但不断出现以下错误：

{'error': 'Response not interpretable as json. Try printing the .text attribute'}

为什么会这样

Answer 1

端点不返回JSON。 这可能意味着您输入的文件名有问题（可能是奇怪/不可接受的字符？）

请尝试此代码以查看它返回的内容，在我的示例中，它始终返回JSON数据：

import requests
import json

def get_movies_from_tastedive(movie):
    d = {"q":movie,"type":"movie","limit":"5"}
    movies = requests.get("https://tastedive.com/api/similar",params=d)
    try:
        return movies.json()
    except Exception as e:
        print(e)
        return movies.text

print("Getting data for movie Seven:")
print(get_movies_from_tastedive("Seven"))
print("\nGetting data for movie Sevssssen:")
print(get_movies_from_tastedive("Sevssssen"))

输出

Getting data for movie Seven:
{u'Similar': {u'Info': [{u'Type': u'movie', u'Name': u'Seven'}], u'Results': [{u'Type': u'movie', u'Name': u'Primal Fear'}, {u'Type': u'movie', u'Name': u'The Usual Suspects'}, {u'Type': u'movie', u'Name': u'The Game'}, {u'Type': u'movie', u'Name': u'Insomnia'}, {u'Type': u'movie', u'Name': u'American History X'}]}}

Getting data for movie Sevssssen:
{u'Similar': {u'Info': [{u'Type': u'unknown', u'Name': u'sevssssen'}, {u'Type': u'unknown', u'Name': u'sevssssen'}], u'Results': []}}