如何传输检测按钮是否被点击的信号？

Question

我想问一下，是否可以使用信号/插槽传输信息，如：“是否单击了此按钮？”

我在这里准备了一些代码

from PyQt5.QtWidgets import *
from PyQt5.QtGui import *
from PyQt5.QtCore import *
import sys


class Worker(QObject):
    def __init__(self, parent=None):
        super(Worker, self).__init__(parent)

    @pyqtSlot(str, str, int, add_one_more_signal)
    def onJob(self, strA, strB, int1, add_one_more_signal):
        print(strA, strB, int1)

        # if the signal detects the btn1 was clicked:
        # print("button 1 is clicked; button 2 is not clicked")

        # if the signal detects the btn2 was clicked:
        # print("button 1 is not clicked; button 2 is clicked")



class MyApp(QWidget):
    signal = pyqtSignal(str, str, int,  add_one_more_signal)
    def __init__(self, parent= None):
        super(MyApp, self).__init__(parent)
        self.initUI()

    def initUI(self):
        self.btn1 = QPushButton("start 1", self)
        self.btn2 = QPushButton("start 2", self)
        self.btn1.clicked.connect(self.start)
        self.btn2.clicked.connect(self.start)

        self.layout = QVBoxLayout()
        self.layout.addWidget(self.btn1)
        self.layout.addWidget(self.btn2)
        self.setLayout(self.layout)
        self.show()

    def start(self):
        otherClass = Worker()
        self.signal.connect(otherClass.onJob)
        self.signal.emit("foo", "baz", 10, self.btn1.clicked(True) or self.btn2.clicked(True)) # How to write this line?

if __name__ == '__main__':
    app = QApplication(sys.argv)
    window = MyApp()
    window.show()
    sys.exit(app.exec_())

请不要误会我。我用我非常少的知识知道如何达到编程的目的。我只是想知道，如何传输信号，它检测按钮是否被点击--老实说，我也想知道信号+插槽的性能

在我的代码中有两个按钮。它们共享相同的子功能。（正如我提到的，就为了这个问题。）单击其中一个时，三个参数从MyApp类传输到Worker类

现在我想引入第四个参数，我也在上面的代码中编写了这个参数。第四个参数只执行一项任务，即发送信息，无论是否单击按钮

所以我的问题是：如果可行，如何编写代码

Answer 1

一个可能的解决方案是发送显示按钮的文本，第四个参数的类型必须是str，为了获得发出信号的对象，我们使用sender()，在这种情况下sender()将是被按下的对象，然后我们获取文本并发送它

class Worker(QObject):
    def __init__(self, parent=None):
        super(Worker, self).__init__(parent)

    @pyqtSlot(str, str, int, str)
    def onJob(self, strA, strB, int1, text):
        print(strA, strB, int1)
        if text == "start 1":
            print("button 1 is clicked")
        elif text == "start 2":
            print("button 2 is clicked")


class MyApp(QWidget):
    signal = pyqtSignal(str, str, int, str)
    def __init__(self, parent= None):
        super(MyApp, self).__init__(parent)
        self.initUI()

    def initUI(self):
        self.btn1 = QPushButton("start 1", self)
        self.btn2 = QPushButton("start 2", self)
        self.btn1.clicked.connect(self.start)
        self.btn2.clicked.connect(self.start)

        self.layout = QVBoxLayout()
        self.layout.addWidget(self.btn1)
        self.layout.addWidget(self.btn2)
        self.setLayout(self.layout)
        self.show()

    def start(self):
        otherClass = Worker()
        btn = self.sender()
        self.signal.connect(otherClass.onJob)
        self.signal.emit("foo", "baz", 10, btn.text())