擅长:python、mysql、java
<p><strong>简短回答</strong></p>
<pre><code>T_1 = [] # outer list, all rows
for j in range(len(A_1)):
T_1.append( [] ) # new inner list, a row
for i in range(len(y_1)):
# last row is T_1[-1] and you append to it
your_value = T0_1 + ((q0_1 / k_1) * y_1[i]) - ((A_1[j] / (2 * k_1)) * y_1[i]**2)
T_1[-1].append(your_value)
</code></pre>
<p><strong>参考</strong></p>
^{pr2}$
<p>您可以通过列表理解来完成。<br/>
在这一点上都不要尝试。<br/>
因为你会犯很多错误。在</p>