擅长:python、mysql、java
<p>根据您的新更新,请使用以下代码:</p>
<pre><code>def countMeans(a):
count = 0
if len(a) > 1:
for i in range(0, len(a)):
val1 = 0 if i == 0 else a[i-1]
try:
val2 = a[i+1]
except:
val2 = 0
if val1 + val2 == 2 * a[i]:
count += 1
else:
count = 1 if a[0] == 0 else 0
return count
</code></pre>