在pycharm中使用Jupyter笔记本命令时出现关键错误5

Question

我偶然发现了一个我不理解或无法找到解决办法的问题

我键入的代码在我的Jupyter笔记本中运行得非常好，但在使用PyCharm时出错

我在PyCharm中输入了以下代码：

df_ticker.loc[df_ticker['Red'] == True, 'Value'] = df_ticker['Open'] - df_ticker['Close']

df_ticker.loc[df_ticker['Red'] == False, 'Value'] = df_ticker['Close'] - df_ticker['Open']

单独使用这些代码并打印它们的值是成功的。 H

但是，当与这些代码行匹配时：

for i in range(1, len(df_ticker)):
if df_ticker.Close[i] > df_ticker.Close[i-1] and df_ticker.Red[i] == False and \
        df_ticker.Value.round(decimals = 0)[i] >= df_ticker.Value.round(decimals = 0)[i-1] \
        and not df_ticker.Close[i-1] >= df_ticker [i-2]:
    rise.append(df_ticker.Close[i])

它返回以下错误：

Traceback (most recent call last):
  File "/Users/benjaminwong/PycharmProjects/Yahoo Finance project/venv/lib/python3.8/site-packages/pandas/core/indexes/base.py", line 2889, in get_loc
    return self._engine.get_loc(casted_key)
  File "pandas/_libs/index.pyx", line 70, in pandas._libs.index.IndexEngine.get_loc
  File "pandas/_libs/index.pyx", line 97, in pandas._libs.index.IndexEngine.get_loc
  File "pandas/_libs/hashtable_class_helper.pxi", line 1675, in pandas._libs.hashtable.PyObjectHashTable.get_item
  File "pandas/_libs/hashtable_class_helper.pxi", line 1683, in pandas._libs.hashtable.PyObjectHashTable.get_item
KeyError: 5

The above exception was the direct cause of the following exception:

Traceback (most recent call last):
  File "/Users/benjaminwong/PycharmProjects/Yahoo Finance project/Rise_Finder 2.py", line 29, in <module>
    and not df_ticker.Close[i-1] >= df_ticker [i-2]:
  File "/Users/benjaminwong/PycharmProjects/Yahoo Finance project/venv/lib/python3.8/site-packages/pandas/core/frame.py", line 2899, in __getitem__
    indexer = self.columns.get_loc(key)
  File "/Users/benjaminwong/PycharmProjects/Yahoo Finance project/venv/lib/python3.8/site-packages/pandas/core/indexes/base.py", line 2891, in get_loc
    raise KeyError(key) from err
KeyError: 5

请帮忙，谢谢您的时间：）

Answer 1

and not df_ticker.Close[i-1] >= df_ticker [i-2]:

及

KeyError: 5

df_ticker.Close[5]或df_ticker[5]不存在

Answer 2

它应该是：

df_ticker.Close[i] > df_ticker.Close[i-2]

我错过了第二关