typeerror:“float”对象在python中不可编辑

Question

我有Md = [20, 30, 40, 50, 60] 用纬度Amp_lat = 1.98和经度Amp_lon = 30.03指向，但是我试图运行以下代码，但是我得到了这个错误

TypeError: 'float' object is not iterable

for distkm in (Md):
    Center = Amp_lat, Amp_lon
    North = vincenty(kilometers=distKm).destination(Point(Amp_lat, Amp_lon), 0).format_decimal()
    East = vincenty(kilometers=distKm).destination(Point(Amp_lat, Amp_lon), 90).format_decimal()
    South = vincenty(kilometers=distKm).destination(Point(Amp_lat, Amp_lon), 180).format_decimal()
    West = vincenty(kilometers=distKm).destination(Point(Amp_lat, Amp_lon), 270).format_decimal()

Answer 1

试试list comprehension，它更方便：

new = [[k] for k in A]

解释

您将获得类型错误，因为您无法将list（）函数应用于类型float的值。此函数将iterable作为参数，且float不可iterable