擅长:python、mysql、java
<p>需要在最后一步中使用字典的items()函数对其进行迭代:</p>
<pre><code>multipleDict = {v:k for k, v in multipleDict.items()}
</code></pre>
<p>或者,如果在步骤3中切换值,甚至不需要这样做,请尝试以下操作:</p>
<pre><code>listyList = [1, 5, 7, 9999]
multiple = [(f, f*100) for f in listyList]
multipleDict = {f[1]:f[0] for f in multiple}
print(multipleDict[700])
</code></pre>