擅长:python、mysql、java
<p>您需要在dict的<code>items()</code>上迭代:</p>
<pre><code>listyList = [1, 5, 7, 9999]
multiple = [(f, f*100) for f in listyList]
multipleDict = {f[0]:f[1] for f in multiple}
multipleDict = {v:k for k, v in multipleDict.items()}
</code></pre>