回答此问题可获得 20 贡献值,回答如果被采纳可获得 50 分。
<p>我一直在查看stack,花了几个小时浏览,试图解决这个问题。
任务是:<br/>
<em>编写一个名为dicerolls的Python函数来模拟掷骰子。你的函数应该有两个参数:掷骰子的次数k和掷骰子的次数n。该函数应模拟随机滚动k个骰子n次,跟踪每个总面值。然后,它应该返回一个字典,其中包含每个可能的总面值出现的次数。因此,将函数调用为diceroll(k=2,n=1000)应该返回一个类似于:{2:19,3:50,4:82,5:112,6:135,7:174,8:133,9:114,10:75,11:70,12:36}</em></p>
<p>到目前为止,我已经成功地定义了骰子函数,但我正在努力将k(掷骰数)添加到骰子函数中。到目前为止,我所拥有的:</p>
<pre><code>from numpy import random
def dice():
return random.randint(1, 7)
def diceroll(number_of_times):
counter = {n : 0 for n in range(2, 13)}
for i in range(number_of_times):
first_dice = dice()
second_dice = dice()
total = first_dice + second_dice
counter[total] += 1
return counter
diceroll(1000)
</code></pre>
<p>输出:
{2: 19,
3: 49,
4: 96,
5: 112,
6: 150,
7: 171,
8: 151,
9: 90,
10: 89,
11: 47,
12:26}</p>
<p>如有任何建议,我们将不胜感激</p>
<p><strong>回答后编辑的代码</strong></p>
<pre><code>import random
def diceroll(k, n, dice_sides=6):
# prepare dictionary with zero values for all possible results
counter = {n : 0 for n in range(k, k*dice_sides + 1)}
# roll all the dice
for i in range(n):
dice_sum = sum(random.choices(range(1, dice_sides + 1), k = k))
counter[dice_sum] += 1
return counter
diceroll(k=2, n=1000)
</code></pre>
<p>输出:
{2: 20,
3: 49,
4: 91,
5: 116,
6: 140,
7: 138,
8: 173,
9: 112,
10: 72,
11: 65,
12:24}</p>