使用Nuba（tqdm不工作）Python时的进度条

Question

我一直在尝试使用numba运行代码，我还添加了一个打印以查看代码的进度：

from numba import jit,njit,prange
import numpy as np
# for minimum reproducible example
a=1e5
ar = np.random.rand(a)
at = np.random.rand(a)
an = np.random.rand(a)
###############################3


tau    = 1        # time lag
window = 6000


@njit(parallel=True)
def func_DB(ar,at,an):
    DBtotal= np.zeros((len(an)-tau))
    k = 0
    for i in prange(0,len(an)-tau,1):
        DBtotal[i] = np.sqrt((ar[i + tau]- ar[i])**2 +(at[i + tau]- at[i])**2 +(an[i + tau]- an[i])**2)
       ## To print the progress
         if i%1e5==0:
            k+=1
            print(k*1e5/len(DBtotal))
    return DBtotal


@njit(parallel=True)
def func_PVI(tau, window):
    PVI = np.zeros((len(DBtotal)))
    k = 0
    for i in prange(int(window/2),len(DBtotal)-int(window/2)): 
        PVI[i] = DBtotal[i]/np.sqrt((np.mean(DBtotal[i-int(window/2):i+int(window/2)]**2)))
       # To print the progress
        if i%1e5==0:
            k+=1
            print(k*1e5/len(DBtotal))
    return PVI 
DBtotal = func_DB(ar,at,an)
PVI     = func_PVI(DBtotal,tau, window)

但是，当代码运行时，我没有得到我期望的结果（即，随着代码的运行，值从0变为1），而是得到以下结果：

Out[:] 0.009479390005044932
      0.009479390005044932
      0.009479390005044932
      0.009479390005044932
      0.009479390005044932
      0.018958780010089864

有人能推荐一种查看代码进度的方法吗

此外，任何提高代码效率的建议都将不胜感激

Answer 1

我将函数分解为若干部分，并在其周围包装了一个TQM

而不是

@jit(nopython=True)
def dothings(A, rows, cols):
    for r in range(rows):
        for c in range(cols):
            stuff...

dothings(data, data.shape[0], data.shape[1])

我曾经

rows=data.shape[0]
@jit(nopython=True)
def dothings(A, cols, r):
#    for r in range(rows):
        for c in range(cols):
            stuff...
    
for r in tqdm.tqdm(range(rows), total=rows):
    dothings(data, data.shape[1], r)

Answer 2

试试这个：

from numba import njit,prange,objmode
@njit(parallel=True)
def harmonic_load_flow_func_time_inside():
    with objmode(time1='f8'):
        time1 = time.perf_counter()
    calc = 0
    for x in prange(1000000):
        calc += x

    with objmode():
        print('time: {}'.format(time.perf_counter() - time1),end='\r')