Discord-Bot中的AFK函数

2024-06-01 06:10:36 发布

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我目前正在尝试使用python(对我来说几乎是全新的东西)在Discord中创建一个机器人。我试图制作一个AFK函数(类似于Dyno的)。这是我的代码:

afkdict = {}
@client.command(name = "afk", brief = "Away From Keyboard",
                description = "I'll give you the afk status and if someone pings you before you come back, I'll tell "
                              "them that you are not available. You can add your own afk message!")
async def afk(ctx, message = "They didn't leave a message!"):
    global afkdict

    if ctx.message.author in afkdict:
        afkdict.pop(ctx.message.author)
        await ctx.send('Welcome back! You are no longer afk.')

    else:
        afkdict[ctx.message.author] = message
        await ctx.send("You are now afk. Beware of the real world!")


@client.event
async def on_message(message):
    global afkdict

    for member in message.mentions:  
        if member != message.author:  
            if member in afkdict:  
                afkmsg = afkdict[member]  
                await message.channel.send(f"Oh noes! {member} is afk. {afkmsg}")
    await client.process_commands(message)

我这里的问题是,使用此函数的用户在再次写入之前都是AFK>afk。我的意图是,无论用户是否使用bot功能,只要用户再次在服务器上讲话,bot都能够删除AFK状态。我知道这是可能的,因为其他机器人都这么做了,但我迷路了,想不出一个办法。 提前谢谢


Tags: inclientyousendmessageifawaitare
1条回答
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1楼 · 发布于 2024-06-01 06:10:36
async def on_message(message):
    global afkdict
    if message.author in afkdict:
       afkdict.pop(message.author)

    for member in message.mentions:  
        if member != message.author:  
            if member in afkdict:  
                afkmsg = afkdict[member]  
                await message.channel.send(f"Oh noes! {member} is afk. {afkmsg}")
    await client.process_commands(message)

我认为应该这样做,但您也可以再次传递ctx或将ctx保存为参数以访问。 但是这个版本不会通知用户,他们不再是afk了

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