如何在Python中向多个异步任务传递参数

Question

现在我有一些代码如下所示：

    userinput1 = abc.....
    userinput2 = abc.....
    userinput3 = abc.....
    
    async def task1():
        do something with userinput1...
        do another thing...
    
    async def task2():
        do something with userinput2...
        do another thing...
    
    async def task3():
        do something with userinput3...
        do another thing...
    
    async def main():
        await asyncio.wait([task1() , task2(), task3()])
    
    if __name__ == '__main__':
        asyncio.get_event_loop().run_until_complete(main())

正如您在上面看到的，我有3个异步函数，它们可以同时完成不同的任务。我想知道是否有任何方法可以根据用户输入轻松创建许多函数？基本上，我希望它能够做到这一点：

    userinput1 = abc.....
    userinput2 = abc.....
    userinput3 = abc.....
    userinput4 = abc.....
    amount_of_needed_functions = 4

一旦获得数据，它就会像下面的脚本一样运行：

    async def task1():
            do something with userinput1...
            do another thing...
        
    async def task2():
            do something with userinput2...
            do another thing...
        
    async def task3():
            do something with userinput3...
            do another thing...
    
    async def task4():
            do something with userinput4...
            do another thing...
        
    async def main():
            await asyncio.wait([task1() , task2(), task3(), task4()])
        
    if __name__ == '__main__':
            asyncio.get_event_loop().run_until_complete(main())

因此，它会使函数基于特定的可验证性（如userinput1），然后执行多次指定的操作（所需函数的数量），然后同时运行所有这些函数。抱歉，这是一个令人困惑的问题，但我完全不知道从哪里开始研究这个问题。谢谢

Answer 1

将用户输入作为参数传递给每个任务：

用于多任务的单一功能

import asyncio

async def function(user_input, input_index):
    print(f'In {input_index} function: {user_input}')


async def main():
    tasks = []
    for input_index in range(1, 4):
        user_input = input(f"Enter input #{input_index}\n")
        tasks.append(asyncio.create_task(function(user_input, input_index)))
    await asyncio.gather(*tasks)


if __name__ == '__main__':
    asyncio.run(main())

多功能多任务

使用字典为每个输入调用所需的方法

import asyncio

async def function1(user_input, input_index):
    print(f'In {input_index} function1: {user_input}')

async def function2(user_input, input_index):
    print(f'In {input_index} function2: {user_input}')

async def function3(user_input, input_index):
    print(f'In {input_index} function3: {user_input}')


FUNCTION_DICTIONARY = { 1 : function1, 2 : function2, 3 : function3 }

async def main():
    tasks = []
    for input_index in range(1, 4):
        user_input = input(f"Enter input #{input_index}\n")
        tasks.append(asyncio.create_task(FUNCTION_DICTIONARY[input_index](user_input, input_index)))
    await asyncio.gather(*tasks)


if __name__ == '__main__':
    asyncio.run(main())

Answer 2

如果所有函数都执行相同的操作，则可以尝试类似的操作

inputs = ['a', 'b', 'c']

async def task(input: str):
    # Do stuff / await stuff
    return input
   
async def main()
    await asyncio.wait(
        [task(arg) for arg in inputs]
    )