python如何识别图像并单击它们

Question

我想做一个脚本，点击图像取决于什么是问，它需要去通过一个图像列表。例如，如果程序要求用户单击绿色圆圈：

question_list = greencircle, redcircle, bluesquare, redtriangle

if(greencircle == greencircle.png){
    pyautogui.click(greencircle.png)
}

有人能帮忙吗

Answer 1

PyAutoGUI有一个名为locateOnScreen()的内置function，如果它能在当前屏幕上找到图像中心，它将返回图像中心的x，y坐标（它拍摄一个屏幕截图，然后对其进行分析）

图像必须与精确匹配才能工作；i、 e.如果你想点击一个button.png，那么按钮图片的大小/分辨率必须与窗口中的按钮相同，程序才能识别它。实现这一点的一种方法是拍摄一个屏幕截图，在画图中打开它，然后只剪下你想要按下的按钮（或者你可以让PyAutoGUI为你做这件事，我将在后面的示例中展示）

import pyautogui

question_list = ['greencircle', 'redcircle', 'bluesquare', 'redtriangle']

user_input = input('Where should I click? ')

while user_input not in question_list:
    print('Incorrect input, available options: greencircle, redcircle, bluesquare, redtriangle')
    user_input = input('Where should I click?')

location = pyautogui.locateOnScreen(user_input + '.png')
pyautogui.click(location)

上面的示例要求您的目录中已经有greencircle.png和所有其他.png文件

PyAutoGUI还可以拍摄screenshots，您可以指定屏幕的哪个区域拍摄pyautogui.screenshot(region=(0, 0, 0, 0))前两个值是要选择的区域左上角的x，y坐标，第三个值是向右多远（x），第四个值是向下多远（y）

以下示例获取Windows 10徽标的屏幕截图，将其保存到文件中，然后使用指定的.png文件单击徽标

import pyautogui

pyautogui.screenshot('win10_logo.png', region=(0, 1041, 50, 39))
location = pyautogui.locateOnScreen('win10_logo.png')
pyautogui.click(location)

您也不必将屏幕截图保存到文件中，只需将其保存为变量即可

import pyautogui

win10 = pyautogui.screenshot(region=(0, 1041, 50, 39))
location = pyautogui.locateOnScreen(win10)
pyautogui.click(location)

让一个程序检测用户是否点击了某个区域（比如说windows 10徽标），需要另一个类似pynput的库

from pynput.mouse import Listener    

def on_click(x, y, button, pressed):
    if 0 < x < 50 and 1080 > y > 1041 and str(button) == 'Button.left' and pressed:
        print('You clicked on Windows 10 Logo')
        return False    # get rid of return statement if you want a continuous loop

with Listener(on_click=on_click) as listener:
    listener.join()

将所有内容放在一起

import pyautogui
from pynput.mouse import Listener

win10 = pyautogui.screenshot(region=(0, 1041, 50, 39))
location = pyautogui.locateOnScreen(win10)

# location[0] is the top left x coord
# location[1] is the top left y coord
# location[2] is the distance from left x coord to right x coord
# location[3] is the distance from top y coord to bottom y coord

x_boundary_left = location[0]
y_boundary_top = location[1]
x_boundary_right = location[0] + location[2]
y_boundary_bottom = location[1] + location[3]


def on_click(x, y, button, pressed):
    if x_boundary_left < x < x_boundary_right and y_boundary_bottom > y > y_boundary_top and str(button) == 'Button.left' and pressed:
        print('You clicked on Windows 10 Logo')
        return False    # get rid of return statement if you want a continuous loop


with Listener(on_click=on_click) as listener:
    listener.join()