如何将xaxis值转换为matplotlib条形图的图例

Question

我正在为来自系列的数据创建条形图。但是，名称（x轴值）非常长。如果将它们旋转90度，则无法读取整个名称并获得图形的良好图像。45度也好不到哪里去。我正在寻找一种方法，用数字1-15标记x轴，然后用图例列出每个数字对应的名称

这是我到目前为止完成的函数，包括从更大的数据帧创建系列

def graph_average_expressions(TAD_matches, CAGE): 
"""graphs the top 15 expression levels of each lncRNA"""

for i, row in TAD_matches.iterrows():
    mask = (
        CAGE['short_description'].isin(row['peak_ID'])
    )#finds expression level for peaks in an lncRNA
    average = CAGE[mask].iloc[:,8:].mean(axis=0).astype('float32').sort_values().tail(n=15)
    #made a new df of the top 15 highest expression levels for all averaged groups 
    #a group is peaks belong to the same lncRNA
    cell_type = list(average.index)
    expression = list(average.values)
    average_df = pd.DataFrame(
        list(zip(cell_type, expression)), 
        columns=['cell_type','expression']
    )
    colors = sns.color_palette(
        'husl', 
        n_colors=len(cell_type)
    )
    p = sns.barplot(
        x=average_df.index, 
        y='expression', 
        data=average_df, 
        palette=colors
    )
    cmap = dict(zip(average_df.cell_type, colors))
    patches = [Patch(color=v, label=k) for k, v in cmap.items()]
    plt.legend(
        handles=patches, 
        bbox_to_anchor=(1.04, 0.5), 
        loc='center left', 
        borderaxespad=0
    )
    plt.title('expression_levels_of_lncRNA_' + row['lncRNA_name'])
    plt.xlabel('cell_type')
    plt.ylabel('expression')
    plt.show()

下面是我正在绘制的数据示例

CD14_monocytes_treated_with_Group_A_streptococci_donor2.CNhs13532         1.583428
Neutrophils_donor3.CNhs11905                                              1.832527
CD14_monocytes_treated_with_Trehalose_dimycolate_TDM_donor2.CNhs13483     1.858384
CD14_monocytes_treated_with_Candida_donor1.CNhs13473                      1.873013
CD14_Monocytes_donor2.CNhs11954                                           2.041607
CD14_monocytes_treated_with_Candida_donor2.CNhs13488                      2.112112
CD14_Monocytes_donor3.CNhs11997                                           2.195365
CD14_monocytes_treated_with_Group_A_streptococci_donor1.CNhs13469         2.974203
Eosinophils_donor3.CNhs12549                                              3.566822
CD14_monocytes_treated_with_lipopolysaccharide_donor1.CNhs13470           3.685389
CD14_monocytes_treated_with_Salmonella_donor1.CNhs13471                   4.409062
CD14_monocytes_treated_with_Candida_donor3.CNhs13494                      5.546789
CD14_monocytes_-_treated_with_Group_A_streptococci_donor3.CNhs13492       5.673991
Neutrophils_donor1.CNhs10862                                              8.352045
Neutrophils_donor2.CNhs11959                                             11.595509

使用上面的新代码，这是我得到的图形，但没有图例或标题。

Answer 1

有点不同的路线。制作一个字符串将x值映射到名称，并将其添加到图形中

制作了我自己的数据框以供说明

from matplotlib import pyplot as plt
import pandas as pd
import string,random
df = pd.DataFrame({'name':[''.join(random.sample(string.ascii_letters,15))
                           for _ in range(10)],
                   'data':[random.randint(1,20) for _ in range(10)]})

制作情节

fig,ax = plt.subplots()
ax.bar(df.index,df.data)

制作图例

x_legend = '\n'.join(f'{n} - {name}' for n,name in zip(df.index,df['name']))

添加图例作为文本艺术家，并调整绘图以适应它

t = ax.text(.7,.2,x_legend,transform=ax.figure.transFigure)
fig.subplots_adjust(right=.65)

plt.show()
plt.close()

---

通过获取并使用文本艺术家的大小和人物的大小，可以使其动态

# using imports and DataFrame from above
fig,ax = plt.subplots()
r = fig.canvas.get_renderer()

ax.bar(df.index,df.data)
x_legend = '\n'.join(f'{n} - {name}' for n,name in zip(df.index,df['name']))
t = ax.text(0,.1,x_legend,transform=ax.figure.transFigure)

# find the width of the Text and place it on the right side of the Figure
twidth = t.get_window_extent(renderer=r).width
*_,fwidth,fheight = fig.bbox.extents
tx,ty = t.get_position()
tx =  .95 - (twidth/fwidth)
t.set_position((tx,ty))

# adjust the right edge of the plot/Axes
ax_right = tx - .05
fig.subplots_adjust(right=ax_right)