在python中从字典列表创建分层json转储

Question

表格：

categories = Table("categories", metadata,
                   Column("id", Integer, primary_key=True),
                   Column("name", String),
                   Column("parent_id", Integer, ForeignKey("categories.id"),
                          CheckConstraint('id!=parent_id'), nullable=True),

)

一个类别可以有多个子项，但只有一个父项。我使用CTE得到了如下字典值列表：例如，对于id:14，parent是13，并从parent 8->；10->；12->；13->；14遍历，其中parent 8没有父id

^{pr2}$

我希望父对象的属性也作为子类别嵌入到列表中，如下所示：

{
  "id": 14, 
  "name": "cat14", 
  "parent_id": 13, 
  "subcats": [
       {
         "id: 8", 
         "name": "cat8", 
         "parent_id":null
       }, 
       {
         "id: 10", 
         "name": "cat10", 
         "parent_id":8
       },  
       {
         "id: 12", 
         "name": "cat12", 
         "parent_id":10
       },   
      and similarly for ids 13 and 14..... 
     ]
}, 
{
  "id": 15, 
  "name": "cat15", 
  "parent_id": 13, 
  "subcats": [
       {
         "id: 8", 
         "name": "cat8", 
         "parent_id":null
       }, 
       {
         "id: 10", 
         "name": "cat10", 
         "parent_id":8
       },  
       {
         "id: 12", 
         "name": "cat12", 
         "parent_id":10
       },   
       and similarly for ids 13, 14, 15..... 
     ]
}

] 请注意，“path_info”已从字典中删除，并且每个id都显示了其详细信息。我想要上面缩进格式的json转储。怎么走？使用Flask0.10，Python2.7

Answer 1

有一种可以接受的方法，只需理解一些列表/dict。在

lst = [{"id": 14, "name": "cat14", "parent_id": 13, "path_info": [8, 10, 12, 13, 14]}, {"id": 15, "name": "cat15", "parent_id": 13, "path_info": [8, 10, 12, 13, 15]}]

master_dct = { d['id'] : d for d in lst}
for d in lst:
    d['subcats'] = [{field : master_dct[i][field] for field in ['id', 'name', 'parent_id']} \
        for i in d['path_info'] if i in master_dct]

import json
with open('out.json', 'w') as f:
    json.dump(lst, f)