擅长:python、mysql、java
<blockquote>
<p>Return the IEEE 754-style remainder of x with respect to y. For finite
x and finite nonzero y, this is the difference <code>x - n*y</code>, where n is the
closest integer to the exact value of the quotient <code>x / y</code>. If <code>x / y</code> is
exactly halfway between two consecutive integers, the nearest even
integer is used for n. The remainder <code>r = remainder(x, y)</code> thus always
satisfies <code>abs(r) <= 0.5 * abs(y)</code>.</p>
</blockquote>
<p>对于模,这是<code>m = x - n*y</code>,其中<code>n</code>是<code>floor(x/y)</code>,因此<code>0 <= m < y</code>而不是<code>abs(r) <= 0.5 * abs(y)</code>表示余数</p>
<p>所以</p>
<pre><code>modulo(2.7, 1) = 0.7
remainder(2.7, 1) = -0.3
</code></pre>