擅长:python、mysql、java
<p>这是经过优化的,并且通过了所有测试用例:</p>
<pre><code>class Result
{
public static int minNum(int samDaily, int kellyDaily, int difference)
{
// No catching up because samDaily is ahead (positive P) and kellyDaily cannot catch up.
if (kellyDaily <= samDaily)
{
return -1;
}
return difference/(kellyDaily - samDaily) + 1;
}
}
</code></pre>