Python内存压缩库

Question

是否有一个Python库允许在不使用实际磁盘文件的情况下操纵内存中的zip归档文件

ZipFile库不允许您更新存档。唯一的方法似乎是将其解压缩到一个目录，进行更改，然后从该目录创建一个新的zip。我想在没有磁盘访问的情况下修改zip存档，因为我将下载它们，进行更改，然后再次上载它们，所以我没有理由存储它们

类似于Java的ZipInputStream/zipoutpstream的东西可以实现这一点，尽管任何避免磁盘访问的接口都可以

Answer 1

PYTHON 3

import io
import zipfile

zip_buffer = io.BytesIO()
with zipfile.ZipFile(zip_buffer, "a", zipfile.ZIP_DEFLATED, False) as zip_file:
    for file_name, data in [('1.txt', io.BytesIO(b'111')), ('2.txt', io.BytesIO(b'222'))]:
        zip_file.writestr(file_name, data.getvalue())
with open('C:/1.zip', 'wb') as f:
    f.write(zip_buffer.getvalue())

Answer 2

第In-Memory Zip in Python条：

Below is a post of mine from May of 2008 on zipping in memory with Python, re-posted since Posterous is shutting down.

I recently noticed that there is a for-pay component available to zip files in-memory with Python. Considering this is something that should be free, I threw together the following code. It has only gone through very basic testing, so if anyone finds any errors, let me know and I’ll update this.

import zipfile
import StringIO

class InMemoryZip(object):
    def __init__(self):
        # Create the in-memory file-like object
        self.in_memory_zip = StringIO.StringIO()

    def append(self, filename_in_zip, file_contents):
        '''Appends a file with name filename_in_zip and contents of 
        file_contents to the in-memory zip.'''
        # Get a handle to the in-memory zip in append mode
        zf = zipfile.ZipFile(self.in_memory_zip, "a", zipfile.ZIP_DEFLATED, False)

        # Write the file to the in-memory zip
        zf.writestr(filename_in_zip, file_contents)

        # Mark the files as having been created on Windows so that
        # Unix permissions are not inferred as 0000
        for zfile in zf.filelist:
            zfile.create_system = 0        

        return self

    def read(self):
        '''Returns a string with the contents of the in-memory zip.'''
        self.in_memory_zip.seek(0)
        return self.in_memory_zip.read()

    def writetofile(self, filename):
        '''Writes the in-memory zip to a file.'''
        f = file(filename, "w")
        f.write(self.read())
        f.close()

if __name__ == "__main__":
    # Run a test
    imz = InMemoryZip()
    imz.append("test.txt", "Another test").append("test2.txt", "Still another")
    imz.writetofile("test.zip")

Answer 3

根据Python docs报告：

class zipfile.ZipFile(file[, mode[, compression[, allowZip64]]])

  Open a ZIP file, where file can be either a path to a file (a string) or a file-like object. 

因此，要在内存中打开文件，只需创建一个类似文件的对象（可能使用BytesIO）

file_like_object = io.BytesIO(my_zip_data)
zipfile_ob = zipfile.ZipFile(file_like_object)