擅长:python、mysql、java
<p>一线解决方案:</p>
<pre><code>>>> a = '41cf4a077a7454'
>>> ''.join('{0:08b}'.format(int(x, 16)) for x in (a[i:i+2] for i in xrange(0, len(a), 2)))
'01000001110011110100101000000111011110100111010001010100'
</code></pre>
<p>或解决方案的扩展:</p>
^{pr2}$