在同一函数中访问子接口值

Question

我有两个类-主接口和子接口

有一个按钮将调用子界面，我试图直接（或几乎立即）获得子工具界面的输出，以便在按钮功能中使用

在我的代码中，如果我执行以下操作：

• 点击“点击我”
• 选中2个选项并点击子界面中的“应用到所选项目”
• “我的dict值”的打印行仍然为空

除非我创建另一个函数get_results，其中self.my_dict将正确显示

因此，我如何对其进行编码，使其在点击“应用…”按钮后，self.my_dict将被更新，而无需创建另一个函数？还是我只是想得太多了

class SubMenuWindow(QtGui.QWidget):
    def __init__(self, menu_items, parent=None):
        super(SubMenuWindow, self).__init__(parent)
        self.my_lyt = QtGui.QVBoxLayout()
        self.checked_options = []
        self.sel = {}

        for menu_name, submenu_name in menu_items.items():
            # Set the main menu item name
            self.groupbox = QtGui.QGroupBox(self)
            self.groupbox.setTitle(menu_name)
            self.groupbox.setLayout(QtGui.QVBoxLayout())
            self.my_lyt.addWidget(self.groupbox)

            if submenu_name:
                sub_txt = [action for action in submenu_name]
                for s in sub_txt:
                    sub_chk = QtGui.QCheckBox(s)
                    self.checked_options.append(sub_chk)
                    self.groupbox.layout().addWidget(sub_chk)

        apply_tag_btn = QtGui.QPushButton('Apply to selected item')
        apply_tag_btn.clicked.connect(self.get_checked_options)

        self.my_lyt.addWidget(apply_tag_btn)
        self.my_lyt.addStretch()

        self.setLayout(self.my_lyt)
        self.show()

    def get_checked_options(self):
        for f in self.checked_options:
            if f.isChecked():
                self.sel[f.parent().title()] = f.text()

class MainWin(QtGui.QWidget):
    def __init__(self, parent=None):
        super(MainWin, self).__init__(parent)

        self.my_dict = {}

        btnA = QtGui.QPushButton('Click Me')
        btnA.clicked.connect(self.get_options)

        btnB = QtGui.QPushButton('Get results')
        btnB.clicked.connect(self.get_results)

        layout = QtGui.QVBoxLayout()
        layout.addWidget(btnA)
        layout.addWidget(btnB)
        self.setLayout(layout)

    def get_options(self):
        sample_dict = {'GrpA' : ['John', 'Zack'], 'GrpB' : ['Alice', 'Phan']}
        self.subWin = SubMenuWindow(sample_dict)

        # I had want to get the values from subWin as soon as User has hit on
        # the 'Apply to selected item' button
        self.my_dict = self.subWin.sel
        print ">>> my dict values : ", self.my_dict
        # do something else from here thereafter...

    def get_results(self):
        print self.subWin.sel

Answer 1

创建新窗口不会被阻止，因此打印语句将在用户选择任何内容之前执行。当用户更改选择时，您可以传入回调以通知调用小部件

例如：

class SubMenuWindow(QtWidgets.QWidget):
    def __init__(self, menu_items, parent=None, callback=None):
        super(SubMenuWindow, self).__init__(parent)
        self.callback = callback
        [...]

    def get_checked_options(self):
        for f in self.checked_options:
            if f.isChecked():
                self.sel[f.parent().title()] = f.text()
        if self.callback:
            self.callback()

并传入回调：

    def get_options(self):
        sample_dict = {'GrpA' : ['John', 'Zack'], 'GrpB' : ['Alice', 'Phan']}
        self.subWin = SubMenuWindow(sample_dict, callback=self.get_results)
        [...]

这样，每当用户单击SubMenuWindow中的应用按钮时，就会调用get_result方法