<P>考虑以下HTML:</P>
<pre><code>html_doc = """
<html><head><title>The Dormouse's story</title></head>
<body>
<p class="title"><b>The Dormouse's story</b></p>
<p class="story">Once upon a time there were three little sisters; and their names were
<a href="http://example.com/elsie" class="sister" id="link1">Elsie</a>,
<a href="http://example.com/tillie" class="sister" id="link3">Millie</a>
<a href="http://example.com/tillie" class="sister" id="link3">Tillie</a>
<a href="http://example.com/lacie" class="sister" id="link2">Lacie</a> and
<a href="http://example.com/tillie" class="sister" id="link3">Tillie</a>;
and they lived at the bottom of a well.</p>
<p class="story">...</p>
"""
soup = bs4.BeautifulSoup(html_doc, 'html.parser')
</code></pre>
<p>如果我想要第二个a标签,我可以:</p>
<pre class="lang-py prettyprint-override"><code> soup.select("a:nth-of-type(2)")
</code></pre>
<p>但是,如果我想选择第二、第三和第五个a标签,我该怎么做?
我试着用下面的方法,这给了我错误</p>
<pre class="lang-py prettyprint-override"><code> soup.select("a:nth-of-type([2, 3, 5])")
soup.select("a:nth-of-type(2, 3, 5)")
</code></pre>
<p>如果您的解决方案不是围绕CSS类,那么最好使用<code>soup.find_all()</code></p>
<pre><code>needed_a_tags = [tag for i, tag in enumerate(soup.find_all('a')) if i in [1,2,4]]
</code></pre>