如何制作一个非列表循环，从110中选择4个随机数，并显示它们，但它们不能相同？

Question

import random
counter = 0
count = 0
counting = 0
valueOne = 0
valueTwo = 0
while counter ==0:
    playerOne = random.randint(1,10)
    number = random.randint(1,10)

就在这里，我感到困惑。它将运行循环，但每次运行时，随机值都会重置，即使第一次打印随机数，第二次也可能打印随机数，以此类推

    if number == playerOne:
        count = count + 1
    if number != playerOne:
        valueOne = playerOne

        if number != valueOne:

            print("lotto number",number)
            counting = counting + 1
        if counting >= 4:
            print("it took you this many trys",count)
            input('play again?')
            counting = 0
            count = 0

Answer 1

应在1-10（含）中列出数字，然后随机抽样

random.sample(range(1,11), 4)

random.sample docs

range docs