如何仅输出列表数据中的字符串？

Question

我的文件读取teamNames.txt文件，该文件为：

Collingwood

Essendon

Hawthorn

Richmond

代码：

file2 = input("Enter the team-names file: ") ## E.g. teamNames.txt

bob = open(file2)
teamname = []

for line1 in bob: ##loop statement until no more line in file
    teamname.append(line1)

print(teamname)

输出为：

['Collingwood\n', 'Essendon\n', 'Hawthorn\n', 'Richmond\n']

我想使其输出为：

Collingwood, Essendon, Hawthorn, Richmond

Answer 1

一个选项是使用replace()函数。我已经修改了您的代码以包含此函数

file2= input("Enter the team-names file: ") ## E.g. teamNames.txt

bob =open(file2)
teamname = []

for line1 in bob: ##loop statement until no more line in file
    teamname.append(line1.replace("\n",""))

print(teamname)

将为您提供以下输出：

['Collingwood', 'Essendon', 'Hawthorn', 'Richmond']

然后可以修改teamname以获得请求的输出：

print(", ".join(teamname))

Answer 2

那怎么办

for line1 in bob:
    teamname.append(line1.strip()) # .strip() removes the \n

print (', '.join(teamname))

.join()进行最终格式化

---

更新。我现在认为一个更具python主义（优雅）的答案是：

file2 = input("Enter the team-names file: ") ## E.g. teamNames.txt

with open(file2) as f:
    teamname = [line.strip() for line in f]

print (', '.join(teamname))

with语句确保在块完成时关闭文件。它现在不再执行for循环，而是使用list comprehension，这是一种通过转换另一个列表（或从iterable object，如file）中的元素来创建列表的酷方法

Answer 3

join方法工作得很好，但是您也可以尝试使用for循环

for name in teamname: # takes each entry separately 
    print name