Python浮点变量始终在comparati中返回为最大值

Question

我的代码中存在变量问题。以下是我的部分代码：

import re
name = raw_input("Input the Character's name: ")
name = name.lower()

season = raw_input("Input the season: ")

rainyday = raw_input("Is it a rainy day? ")
total_time = raw_input("What time is it?(Input as e.g 1.30 am")
non_decimal = re.compile(r'[^\d.]+')
timel = non_decimal.sub('', total_time)
float(timel)
print timel
#ALEX
if name == "alex":
    if rainyday == "yes":
        if "am" in total_time:
            if time > 8.00:
                print("He's in the entryway of his house until 1:00 PM")
            else:
                print("He's in his room until 8:00 AM")
                print("!")
        elif timel < 1:
            print("He's in the entryway of his room until 1:00 PM")
            print("y")
        elif timel < 4.2:
            print("He's leaving his room to go to the dog pen until 6:30 PM")
        elif timel < 6.3:
            print("He's at the dog pen until 6:30")
        elif timel < 8.0:
            print("He's in the entryway of his house until 8:00 P.M")
        elif timel < 10.0:
            print("He's standing by the dresser in his room")
        else:
            print("He's sleeping")

每当我输入total_time作为一个带有“pm”的数字，我就会得到else语句“他在睡觉” 我在shell上运行的这些代码行说明了我的问题：

>>> print timel
2
>>> timel < 3
False
>>> 2 < 3
True
>>> timel < 1000000000
False

似乎timel始终是一个未定义的数字，它比其他任何东西都大，即使它已经被定义。我非常感谢您对这个问题的帮助

Answer 1

timel = non_decimal.sub('', total_time)
float(timel)

最后一行不会将timel转换为floatfloat无法正常工作

在此之后，timel仍然是一个字符串，并且比较时没有错误，但是在Python2中使用整数/浮点数会产生奇怪/意外的结果（在Python3中，它失败了，出现异常（unorderable types: str() < int()），这至少指出了错误）

修正：

timel = float(non_decimal.sub('', total_time))

Answer 2

您希望使用float(timel)将字符串转换为浮点数

float( a )返回转换为浮点的a，但不接触原始参数

因此，行应该是timel = float(timel)以实际转换timel