我想每秒播放一次滴答声，并根据算法计时

Question

我想每秒钟播放一次滴答声，但计时是基于算法的

我试过了

def sound(self):
    if self.second_display == 1.0:
        windsound.PlaySound("tock", winsound.SND_FILENAME)

但它不起作用 tock.wav也已与代码位于同一文件夹中

TICK_TIME = 2**6

def display(self):
    self.seconds = self.time // 60
    self.minutes=self.seconds//60
    self.hour_display = self.minutes // 60
    self.minute_display = self.minutes % 60
    self.second_display = self.seconds % 60
    self.millisecond_display = self.time % 60
    self.alltime = self.hour_display, self.minute_display, 
    self.second_display, self.millisecond_display
    self.alltime2 = [self.hour_display, self.minute_display, 
    self.second_display, self.millisecond_display]
    self.LDCDisplay.display("%02d:%02d:%02d.%02d" % (self.alltime))



def sound(self):
    if self.second_display == 1.0:
        windsound.PlaySound("tock", winsound.SND_FILENAME)


def do_start(self):
    if self.onRunning == False:
        self.onRunning=True
        self.StartButton.setText("PAUSE")
        self.timer.start(1)
        self.StartButton.clicked.connect(self.do_pause)


def tick(self):
    self.time += TICK_TIME/1000
    self.display()


def do_reset(self):
    if self.onRunning==False:
        self.LDCDisplay.display("00:00:00.00")
        self.time=0
    elif self.onRunning==True:
        self.time=0
    self.tableWidget.setRowCount(0)
    self.Milli.clear()
    self.x = 0

def do_pause(self):
    if self.onRunning==True:
        self.onRunning=False
        self.timer.stop()
        self.StartButton.setText("START")
        self.StartButton.clicked.connect(self.do_start)