如何计算列中每种类型的标签并将其保存在变量中？

Question

我必须计算数据帧列中出现1和0的时间数。我尝试了以下代码：

count_own_party = len(df['Deviation from Partisanship']== 1)
count_opposing_party = len(df['Deviation from Partisanship'] == 0)

print(count_own_party)
print(count_opposing_party)

这两个值的输出相同：7854。虽然从可以清楚地看到1的数量大于0的数量

Answer 1

为此，熊猫中有一个功能： ^{}：

value_count=df['Deviation from Partisanship'].value_counts()
count_0=value_count[0]
#count_0=value_count['0'] # if it is str
count_1=value_count[1]
#count_1=value_count['1'] # if it is str

---

以下是一个例子：

print(df)
    Mnth  Income
0    Jan      80
1    Feb      80
2    Mar      50
3  April      60
4    May      60

---

value_count=df['Income'].value_counts()
print(value_count)



60    2
80    2
50    1
Name: Income, dtype: int64

---

count_60 = value_count[60]
print(count_60)
#2