这可能很简单,但为什么re.sub不能在下面的场景中工作?我想用“z3”代替“z4”
import re
group2="(a1, a2, a3, a4, z1, z2, z3, z4);"
print("group2=",group2)
re.sub('z4','z3',group2)
print("modified gorup2=",group2)
以下是输出:
group2= (a1, a2, a3, a4, z1, z2, z3, z4);
modified gorup2= (a1, a2, a3, a4, z1, z2, z3, z4);
Process finished with exit code 0
re.sub
将返回一个新字符串 进口稀土输出
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