random.randint生成错误的数字

Question

所以我做了一个快速骰子辊（D&；D） 当我试着掷骰子时，它只会产生从1到4的数字

import random


def d4():
    x = (random.randint(1,4))
    print(x)

def d6():
    x = (random.randint(1,6))
    print(x)

def d8():
    x = (random.randint(1,8))
    print(x)

def d10():
    x = (random.randint(1,10))
    print(x)

def d12():
    x = (random.randint(1,12))
    print(x)

def d20():
    x = (random.randint(1,20))
    print(x)

def d100():
    x = (random.randint(1,100))
    print(x)


choice = input("What dice will you roll: ")


if choice == "d4" or "4":
    d4()
elif choice == "d6" or "6":
    d6()
elif choice == "d8" or "8":
    d8()
elif choice == "d10" or "10":
    d10()
elif choice == "d12" or "12":
    d12()
elif choice == "d20" or "20":
    d20()
elif choice == "d100" or "100":
    d100()
else:
    print(random.randint(1,20))

例如，当我把我的输入作为d100，我只能得到1，2，3，或4！ 到底怎么回事

Answer 1

如果您的陈述不正确，应如下所示：

if choice == "d4" or choice == "4":
    d4()

您这样做的方式使“4”的值为True，因此if总是进入第一个语句，即D4