<p>你可以使用itemgetter</p>
<p>请尝试以下操作：
编辑：改为打印每行的排序列表的函数</p>
<pre><code>from operator import itemgetter
students = [["White", "Snow", 9, "F", 3.56],
["Sprat", "Jack", 12, "M", 2.0],
["Contrary", "Mary", 9, "F", 3.674],
["Dumpty", "Humpty", 11, "M", 2.342],
["Bunny", "Easter", 10, "M", 4.233],
["Wonderland", "Alice", 10, "F", 3.755],
["Bunyon", "Paul", 11, "M", 1.434],
["Penny", "Henny", 9, "F", 2.54],
["Hatter", "Mad", 11, "M", 4.522],
["Munk", "Chip", 10, "M", 3.0],
["Hood", "Red Riding", 10, "F", 3.137],
["Bunny", "Bugs", 11, "M", 2.12],
["Duck", "Daffy", 11, "M", 3.564],
["Ant", "Atom", 12, "M", 3.333],
["Mouse", "Mickey", 10, "M", 3.975],
["Brown", "Charlie", 9, "M", 1.25]]
def printSortedStudents():
sortedStudents = sorted(students, key=itemgetter(4))
# You can change the index value of itemgetter(4) to define what index to sort with.
for l in sortedStudents:
print (l)
printSortedStudents()
</code></pre>
<p>结果应该是这样的：
函数按每个列表最后一个值中的数字排序</p>
<pre><code>['Brown', 'Charlie', 9, 'M', 1.25]
['Bunyon', 'Paul', 11, 'M', 1.434]
['Sprat', 'Jack', 12, 'M', 2.0]
['Bunny', 'Bugs', 11, 'M', 2.12]
['Dumpty', 'Humpty', 11, 'M', 2.342]
['Penny', 'Henny', 9, 'F', 2.54]
['Munk', 'Chip', 10, 'M', 3.0]
['Hood', 'Red Riding', 10, 'F', 3.137]
['Ant', 'Atom', 12, 'M', 3.333]
['White', 'Snow', 9, 'F', 3.56]
['Duck', 'Daffy', 11, 'M', 3.564]
['Contrary', 'Mary', 9, 'F', 3.674]
['Wonderland', 'Alice', 10, 'F', 3.755]
['Mouse', 'Mickey', 10, 'M', 3.975]
['Bunny', 'Easter', 10, 'M', 4.233]
['Hatter', 'Mad', 11, 'M', 4.522]
</code></pre>
