擅长:python、mysql、java
<p>必须合并<code>daysHoursMinutesSecondsFromSeconds</code>生成的元组</p>
<p><code>% (daysHoursMinutesSecondsFromSeconds(dateDiffInSeconds(now, injustice2)) + daysHoursMinutesSecondsFromSeconds(dateDiffInSeconds(now, fridaythe13th)) + daysHoursMinutesSecondsFromSeconds(dateDiffInSeconds(now, shadowofwar)))</code></p>
<p>还要注意包围的<code>()</code></p>
<p>否则,您将发送一个大小为3的元组,其中包含从<code>daysHoursMinutesSecondsFromSeconds</code>返回的值:</p>
<pre><code>(14, 20, 5, 6),
(24, 20, 5, 6),
(112, 20, 5, 6)
</code></pre>
<p>这被认为是3个值,而不是12个值</p>
<p>当我们将元组与<code>+</code>合并时,它将是正确的:</p>
<pre><code>(14, 20, 5, 6, 24, 20, 5, 6, 112, 20, 5, 6)
</code></pre>
<p>还要注意,当你遇到这样的问题时,<code>print</code>是你的朋友</p>