擅长:python、mysql、java
<p>好的,这就是我们所拥有的</p>
<pre><code>a = StringIO(""""","Athens","Barcelona","Brussels"
"Athens",0,3313,2963
"Barcelona",3313,0,1318
"Brussels",2963,1318,0""")
df = pd.read_csv(a,sep=',',engine='python')
</code></pre>
<p>打印(df)</p>
<pre><code> Unnamed: 0 Athens Barcelona Brussels
0 Athens 0 3313 2963
1 Barcelona 3313 0 1318
2 Brussels 2963 1318 0
df.loc[:,'Athens':].values
</code></pre>
<p><strong>输出</strong></p>
<pre><code>array([[ 0, 3313, 2963],
[3313, 0, 1318],
[2963, 1318, 0]])
</code></pre>
<hr/>
<p>pd.至\U csv</p>
<pre><code>[i for i in df.loc[:,'Athens':].to_csv(header=None).split('\n') if i ]
['0,0,3313,2963', '1,3313,0,1318', '2,2963,1318,0']
</code></pre>