我有下面的错误处理程序(实际上是旁路程序)装饰程序-
import functools
def exception_safe(*args):
ErrList = tuple(args)
def decorator(f):
@functools.wraps(f)
def wrapper(*args, **kwargs):
if ErrList:
try:
result = f(*args, **kwargs)
print(f'No error!')
return result
except ErrList as err:
print(f'got error!')
else:
try:
result = f(*args, **kwargs)
print(f'No error!')
return result
except Exception as err:
print(f'got error!')
return wrapper
return decorator
即使我仍然从pytests得到下一个断言错误,告诉我函数名是decorator:
为什么会这样?我什么都试过了
exception_safe
需要给定参数,即使没有:相关问题 更多 >
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