如何在Python中逐行遍历一个表并将其放入列表中

Question

列表1

0, 19.2, 20.3, 21.3, 23.5, 24.6, 25.2, 25.4, 26.2, 26.3, 26.4, 8655, Light
26.2, 25.7, 25.2, 25.3, 22.3, 21.2, 20, 19.2, 19.1, 0, 0, 8655 , Light
0, 0, 54.2, 56.3, 62.3, 63.3, 65.2, 65.3, 65.3, 65.4, 65.4, 8483, Fan
65.4, 65.2, 65.1, 64.2, 63.2, 62.5, 61.3, 56.4, 53.8, 53.2, 0, 8483, Fan
32.3, 33.6, 34.2, 36.3, 34.1, 32.3, 33.6, 33.5, 33.2, 33.3, 33.3, 8470, Fridge
32.3, 34.6, 35.2, 36.3, 34.1, 32.1, 33.6, 33.3, 33.2, 33.3, 33.3, 8470, Fridge
0, 129.3, 2235.6, 2236.2, 2235.5, 2232.3, 2235.6, 2234.2, 2235.2, 2235.4, 2235.6, 8903, WaterHeater
2236.4, 2235.2, 2235.6, 2236.2, 2235.5, 2232.3, 2235.6, 2234.2, 1992.5, 119.3, 0, 8903, WaterHeater

问：如何编写程序，使其逐行逐列地遍历列表，并附加到一个列表中（用于K近邻预测）

列表：[0，19.2，20.3，21.3，23.5，24.6，25.2，25.4，26.2，26.3，26.4，8655，浅色]

Such that it will be in a list after convert to 2D Array 
List:[[0],
     [19.2],
     [20.3],
     [21.3],
     [26.4],
     [Light]]

Answer 1

你可以使用下面的代码

l = [0, 19.2, 20.3, 21.3, 23.5, 24.6, 25.2, 25.4, 26.2, 26.3, 26.4, 8655, 'Light']

final_list=[]
for i in l:
    final_list.append([i])

如果你想遍历一个我认为是列表列表的表，那么使用下面的代码

l1 = [0, 19.2, 20.3, 21.3, 23.5, 24.6, 25.2, 25.4, 26.2, 26.3, 26.4, 8655, 'Light']
[26.2, 25.7, 25.2, 25.3, 22.3, 21.2, 20, 19.2, 19.1, 0, 0, 8655 , 'Light']
[0, 0, 54.2, 56.3, 62.3, 63.3, 65.2, 65.3, 65.3, 65.4, 65.4, 8483, 'Fan']
[65.4, 65.2, 65.1, 64.2, 63.2, 62.5, 61.3, 56.4, 53.8, 53.2, 0, 8483, 'Fan']
[32.3, 33.6, 34.2, 36.3, 34.1, 32.3, 33.6, 33.5, 33.2, 33.3, 33.3, 8470, 'Fridge']
[32.3, 34.6, 35.2, 36.3, 34.1, 32.1, 33.6, 33.3, 33.2, 33.3, 33.3, 8470, 'Fridge']
[0, 129.3, 2235.6, 2236.2, 2235.5, 2232.3, 2235.6, 2234.2, 2235.2, 2235.4, 2235.6, 8903, 'WaterHeater']
[2236.4, 2235.2, 2235.6, 2236.2, 2235.5, 2232.3, 2235.6, 2234.2, 1992.5, 119.3, 0, 8903, 'WaterHeater']

final_list=[]

for l in l1:
    for i in l:
        final_list.append([i])

你的结果会出现在最终的名单上