如何替换列表特定元素的某些部分？

Question

如何替换列表中某些项目的一部分(Python 3.x）假设我有一个列表：

x = ["part2keep removeMe", "saveme removeMe", "third length to throw it off removeMe", "element to save", "KeepThisPart"]

如果我只想删除“removeMe”部分，你会怎么做？到目前为止我有：

def replaceExampleA(x, y):
    for i in x:
        if i[len(i)-8:len(i)-1] == "removeMe":
            y.append(i[0: -12])
        else:
            y.append(i)

编辑：刚刚意识到我犯了一个错误-列表更像这样： x = ["part2keep removeMe 123", "saveme removeMe 12", "third length to throw it off removeMe 83", "element to save", "KeepThisPart"]

我也需要用“removeMe”从元素中去掉数字。谢谢

Answer 1

您可以使用regex来确保代码总是在removeMe出现在字符串末尾时才被剥离：

import re
x = ["part2keep removeMe", "saveme removeMe", "third length to throw it off removeMe", "element to save", "KeepThisPart"]
new_x = [re.sub('\sremoveMe$', '', i) for i in x]

输出：

['part2keep', 'saveme', 'third length to throw it off', 'element to save', 'KeepThisPart']

Answer 2

x = [s.replace('removeMe', '') for s in x]

Answer 3

这可以通过列表理解来完成

x = ["part2keep removeMe", "saveme removeMe", "third length to throw it off removeMe"]

print(y.replace(' removeMe', '') for y in x)