表示目录的嵌套字典

2024-09-27 21:26:26 发布

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文本文件包含有关课后活动的信息(名称、每月价格、天数和时间),如下所示:

Swimming,20,Monday,15,Monday,17,Wednesday,18,Friday,15
Football,20,Tuesday,18,Wednesday,17,Wednesday,18,Thursday,19
Ballet,40,Monday,18,Tuesday,18,Wednesday,16,Thursday,16,Friday,17

为了表示课程目录,我创建了一个嵌套字典,格式如下:

{'Swimming': {'Price': '20', 'Dates': {'Monday': ['15', '17'], 'Wednesday': ['18'], 'Friday': ['15']}}, 'Football': {'Price': '20', 'Dates': {'Tuesday': ['18'], 'Wednesday': ['17', '18'], 'Thursday': ['19']}}, 'Ballet': {'Price': '40', 'Dates': {'Monday': ['18'], 'Tuesday': ['18'], 'Wednesday': ['16'], 'Thursday': ['16'], 'Friday': ['17']}}}

代码如下:

    with open("fil.txt", "r") as f:
        catalogue = {}
        while True:
            content = f.readline().strip()
            if not content: break
            content = content.split(',')
            u[content[0]] = {}
            u[content[0]]['Price'] = content[1]
            u[content[0]]['Dates'] = {}
            for i in range(2,len(content),2): 
                if content[i] in u[content[0]]['Dates']:
                    u[content[0]]['Dates'][content[i]].append(content[i+1])
                else:
                    u[content[0]]['Dates'][content[i]] = [content[i+1]]

我的问题是:有没有更简单的方法来实现这样的字典?或者应该用另一个数据结构来表示目录而不是这个


Tags: in目录if字典contentpricedatesmonday
2条回答

我只会写一个类

from collections import defaultdict

class SportClass:
    def __init__(self, name, price, *times):
        self.name = name
        self.price = float(price)
        self.days = defaultdict(list)
        for day, hour in zip(times[::2], times[1::2]):
            self.days[day].append(int(hour))

with open('fil.txt') as fp:
    classes = [SportClass(*line.split(',')) for line in fp if line.strip()]

这是通过^{}使用嵌套字典结构的一种方法

from collections import defaultdict

u = defaultdict(lambda: defaultdict(lambda: defaultdict(list)))

with open("fil.txt", "r") as f:
    catalogue = {}
    while True:
        content = f.readline().strip()
        if not content: break
        content = content.split(',')
        u[content[0]]['Price'] = content[1]
        for i in range(2,len(content),2): 
            u[content[0]]['Dates'][content[i]].append(content[i+1])

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