我试图用Python做数据库GUI应用程序,但我不能更新表。没有错误,但我运行程序后,我看Mysql工作台没有任何变化
class DB:
def __init__(self):
self.conn = mysql.connector.connect(host='localhost', database='databese', user='user',
password='password')
self.cur = self.conn.cursor()
self.conn.commit()
def update(self, isim):
self.conn.commit()
self.cur.execute("UPDATE hakemler SET durum='UYGUNSUZ' WHERE isim='%s' ",isim)
def updateback(self, isim):
self.cur.execute("UPDATE hakemler SET durum='UYGUN' WHERE isim='%s'",isim)
self.conn.commit()
db = DB()
def çıkar():
db.update(id.get())
def gerial():
db.updateback(hakem1.get())
hakem = StringVar()
hakem1= StringVar()
id = IntVar()
entry1 = tk.Entry(mazeretli, width=20, textvariable=id)
entry1.grid(row=1, column=1)
button1 = tk.Button(mazeretli, text="Kişiyi Listeden Çıkar", command=çıkar)
button1.grid(row=2, column=2)
entry2 = tk.Entry(mazeretli, width=20, textvariable=hakem1)
entry2.grid(row=3, column=1)
button2 = tk.Button(mazeretli, text="Kişiyi Geri Al", command=gerial)
button2.grid(row=4, column=2)
没有错,梅塞格斯什么的。代码就是不起作用
你的问题是:
数据库操作要求在操作之后
commit
,以便将更改写入数据库。你把顺序颠倒了。替换订单:相关问题 更多 >
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