在打印语句中使用已随机选择的数字

Question

所以，我正在创建一个Python游戏，在其中你必须打击一个怪物。玩家有3种技能，它们造成的伤害总是相同的。怪物造成伤害，但每次都是随机的。我想有随机伤害数字分开，所以我可以创建一个总结后，每轮举例来说，如果球员做了100毫克怪物做了42毫克你的生命值将显示在这一轮后。玩家有100点生命，每次战斗都应该更新，但不是刷新。所以在第一轮之后，玩家的生命值为：58，怪物的生命值为：900 第二轮选手在第十局中打出100分 玩家气血左：48怪物气血左：800

ability = input("Press A for a melee hit, B for a firespell and C for a thunder").capitalize()
if ability == "A":
    print("Monster took 10 hp damage")
elif ability == "B":
    print("Monster took 40 hp damage")
elif ability == "C":
    print("Monster took 100 hp damage")
print("You have recieved that much damage from the monster: ", random.randrange(100))

如果有人能帮我，我会很高兴的！ 已经提前谢谢了

Answer 1

若要保存值以供以后使用，请将其存储在变量中：

ability = input("Press A for a melee hit, B for a firespell and C for a thunder").capitalize()
if ability == "A":
    print("Monster took 10 hp damage")
elif ability == "B":
    print("Monster took 40 hp damage")
elif ability == "C":
    print("Monster took 100 hp damage")
damage = random.randrange(100)
print("You have recieved that much damage from the monster: ", damage)
health -= damage

在Python3.8中，赋值表达式允许您在print（）的中间执行此操作：

ability = input("Press A for a melee hit, B for a firespell and C for a thunder").capitalize()
if ability == "A":
    print("Monster took 10 hp damage")
elif ability == "B":
    print("Monster took 40 hp damage")
elif ability == "C":
    print("Monster took 100 hp damage")
print("You have recieved that much damage from the monster: ",
      (damage := random.randrange(100)))