擅长:python、mysql、java
<p>更简单的方法是遍历外循环中的<code>look_here_string</code></p>
<pre><code>search_string = '1abc'
look_here_string = ['dedakloera', 'tuau', '1abcdefg']
ind_to_remove = []
for i,s in enumerate(look_here_string):
for e in search_string:
if not e in s:
ind_to_remove.append(i)
print e, 'not in', s
break
else:
print e, 'in', s
for i in ind_to_remove[::-1]:
del look_here_string[i]
</code></pre>