import random
def create_cards():
deck = []
for i in range(21):
suits = ["♥","♦","♠","♣"]
numbers = ['1','2','3','4','5','6','7','8','9','10','K','Q','J']
card = (random.choice(numbers) + random.choice(suits))
deck.append(card)
return deck
def create_piles():
pile1 = []
pile2 = []
pile3 = []
for k in range(7):
pile1.append(deck.pop())
pile2.append(deck.pop())
pile3.append(deck.pop())
return piles
def user_input():
print (pile1, pile2, pile3)
choice = input("Which pile is your card in?")
if choice == 1:
deck =
elif choice == 2:
deck =
else:
deck =
def trick():
print(0)
deck = create_cards()
piles = create_piles()
如何解决这个问题(我试过将函数create\u piles放在user\u输入括号中,但仍然显示为未定义)
看起来最简单的解决方法是简单地更改函数,将桩作为参数。像这样:
代码无法工作的原因是函数试图访问不在其作用域中的变量。请花点时间阅读更多关于范围的内容:Short Description of the Scoping Rules?
另外,应该用4个空格而不是2个空格缩进
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