列表索引在搜索算法中已过时

Question

我正在试图找出代码中的问题：
https://repl.it/@lerowhou/VerifiablePunyRobots

你能看看吗

Answer 1

arr = [1,2,3,4,5,6,7,8,9,10]
n = int(input())

if n in arr:
    print("The element is there and it's position is %d" %arr.index(n))
else:
    print("The element is not in the list")