通过startswith获取列表中的项

Question

我有以下清单：

['/my/file.py', 'parallel=2', 'parts=4']

如何提取上面的“2”？现在我有：

if 'parallel=' in argv:
    parallel = ?? # item.split('parallel=')[1]
else:
    parallel = None

Answer 1

您可以使用列表理解：

>>> [i.split('=')[1] for i in a if 'parallel' in i]
['2']

Answer 2

>>> v
['/my/file.py', 'parallel=2', 'parts=4']
>>> for thing in v:
        if 'parallel' in thing:
            print thing.split('='), thing.split('=')[-1]
            print thing.partition('='), thing.partition('=')[-1]


['parallel', '2'] 2
('parallel', '=', '2') 2