<p>我认为除了最后的迭代之外,您的代码还遇到了一些问题。下面是一些建议和评论,我相信可以达到你的目的</p>
<pre><code>from random import shuffle
# Function for generating 21 random cards
def makedeck():
# Create 52 cards by suit and cardtype
listy = [card + suit for card in ['A','2','3','4','5','6','7','8','9','10','J','Q','K'] for suit in ['D','H','S','C']]
# Shuffle the list
shuffle(listy)
# Choose only the first 21 items of that list
listy = listy[:21]
return listy
# Function for dividing 21-card deck into 3 equally-sized piles
def dealdeck(listy):
# Iterate over listy, stepping by 3, starting with the first, second, and third item
list1 = listy[::3]
list2 = listy[1::3]
list3 = listy[2::3]
# Return the three lists as three items to correspond to the three piles of the call
return list1, list2, list3
# This works
def makepiles(pile1,pile2,pile3):
print("Pile 1\t\tPile 2\t\t Pile 3\t\t")
for i in range(7):
print(pile1[i],"\t\t",pile2[i],"\t\t",pile3[i],"\t\t")
# This works
def usercardpile():
userinput = input("What pile is your card in?")
if userinput == "1" or userinput.title() == "One":
return 1
elif userinput == "2" or userinput.title() == "Two":
return 2
elif userinput == "3" or userinput.title() == "Three":
return 3
else:
print("Please only write 1, 2 or 3")
return usercardpile()
listy = makedeck()
pile1, pile2, pile3 = dealdeck(listy)
for i in range(1,4):
# Because this function does not return anything, it should be run on its own, and not assigned to a variable
makepiles(pile1,pile2,pile3)
userspile = usercardpile()
# Now you want to re-order the piles based on user input. Because these are lists, you can simply add them together in a new order to create a newly arranged list
if userspile == 1:
newlisty = pile2 + pile1 + pile3
elif userspile == 2:
newlisty = pile1 + pile2 + pile3
else:
newlisty = pile1 + pile3 + pile2
# Now you create new piles based on the re-sorted list and re-iterate
pile1, pile2, pile3 = dealdeck(newlisty)
# Uses .format method instead
print("Your card is {}".format(newlisty[10]))
</code></pre>