比较python中两个字典列表中的不同键

Question

我试着比较两个字典列表以替换相等的值。例如：

d1 = [{'a': 'hello', 'b':'world','c':'this','d':'is'},{'a':'ddd' ,'b': 'www','c':'hah','d':'tt'},.....]
d2 = [{'Q': 'hello', 'H':'target_word','K':'that','N':'was'},{'Q':'world' ,'H': 'target_word','K':'hah','N':'txt'},.....]

有人能告诉我如何比较d1中的键（'a'，'b'）和d2中的'Q'如果它们有相同的值，那么它必须将d1中的'a'和'b'值替换为d2中的'H'值，即'target\u word'

这是我的一次尝试：

for i in d1:
   for j in d2:
    for k in i.keys():
        for k1 in j.keys():
            if j[k1] == i[k]:
                i[k] = j ['H']
                list.append(i[k])

Answer 1

这看起来怎么样

d1 = [{'a': 'hello', 'b':'world','c':'this','d':'is'},{'a':'ddd' ,'b': 'www','c':'hah','d':'tt'}]
d2 = [{'Q': 'hello', 'H':'target_word','K':'that','N':'was'},{'Q':'world' ,'H': 'target_word','K':'hah','N':'txt'}]

for input in d1:
    for queries in d2:
        for val in ("a", "b"):
            if input[val] == queries["Q"]:
                input[val] = queries["H"]

输出：

>>> d1
[{'a': 'target_word', 'c': 'this', 'b': 'target_word', 'd': 'is'}, {'a': 'ddd', 'c': 'hah', 'b': 'www', 'd': 'tt'}]